[hpsdr] Some thoughts on plug-in board layout

[Leon Heller]

----- Original Message ----- 
From: "Lyle Johnson" <kk7p at wavecable.com>
To: "Philip Covington" <p.covington at gmail.com>; "Steven Bible" 
<n7hpr at tapr.org>
Cc: "Open High Performance SDR Project" <hpsdr at hpsdr.org>
Sent: Friday, May 26, 2006 3:03 PM
Subject: Re: [hpsdr] Some thoughts on plug-in board layout


> ***** High Performance Software Defined Radio Discussion List *****
>
> Using Phil's sketch as a starting point.
>
> 1) a 100mm x 100mm board, with the DIN connector centered, has a nominal
> distance of 0.300" from the edge of the DIN connector to the edge of the
> PC board.
>
> 2) Phil suggests we need at least 12,7mm (0.500").  This means we need
> to add 0.200" to the side of the PCB that has the I/O connectors.  On
> Phil's drawing this is towards the left; on a PCB layout looking at the
> component side, this is on the right.
>
> 3) Just to be safe, I'll add 0.300" (7,62 mm) to that side of the PCB.
> This will allow plenty of margin for error.  We have to position ATLAS
> with custom mounting holes in a PC case, so having a little extra depth
> here should not be a problem.
>
> 4) The rest of the additional size for the 120mm width will be added to
> the opposite side of the PCB.  This is (20 - 7,62 = ) 12,38mm, or 0.490".
>
> 5) The datum for the PCB now falls on the lower *right* corner, making
> all of the X offsets negative since we're in the 2nd quadrant instead of
> the first quadrant.  This gives us a consistent reference location for
> any length of PC board: 120mm, 160mm, 185mm, etc.
>
> ***
>
> Given the above, I locate pin A1 of the 96-pin DIN connector at location
>  (-18,4mm, 5.3mm) or  (-0.725", 0.210").
>
> Steve, Phil, do you concur that this location will work?

Did you look at my PCB with the connector? It's in metric but I could easily 
convert it to imperial in the CAD system.

73, Leon 

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