[hpsdr] I didn't think it would happen again "PING"

John B. Stephensen kd6ozh at comcast.net
Thu Aug 24 06:29:16 PDT 2006


The carrier is just 2 DC levels (I and Q) at baseband which are the cosine
and sine of the phase angle of the carrier multplied by the amplitude of the
carrier.

73,

John
KD6OZH

----- Original Message ----- 
From: "Murray Lang" <murray.lang at metoceanengineers.com>
To: <hpsdr at hpsdr.org>
Cc: <hpsdr at hpsdr.org>
Sent: Thursday, August 24, 2006 02:58 UTC
Subject: Re: [hpsdr] I didn't think it would happen again "PING"


> ***** High Performance Software Defined Radio Discussion List *****
>
> Thanks Eric,
>
> By baseband I assume this means I/Q. But what needs to be shifted is the
> carrier, not the modulation. Maybe you have answered that and I just can't
> see it. Apologies if this the case.
>
> Murray - VK6HL
>
> At 10:37 AM 24/08/2006, Eric Blossom wrote:
> >On Thu, Aug 24, 2006 at 09:22:30AM +0800, Murray Lang wrote:
> > > ***** High Performance Software Defined Radio Discussion List *****
> > >
> >
> > >
> > > I have a rudimentary understanding of QSD. My question was really a
more
> > > specific one: what is the mathematical function applied to I and Q in
> > > software that will produce a constant phase shift on the carrier that
it
> > > modulates? I wasn't really expecting anyone to answer. When I have a
> > better
> > > understanding of the math (I'm working on it) then I'll be able to
answer
> > > it myself. Something doesn't smell right though - something about
> > frequency
> > > response of the I/Q output. Anyway, I'll get over it.
> >
> >You can apply a constant phase shift of theta radians of a complex
> >baseband signal by multiplying it by e^(j theta) == cos(theta) +
> >sin(theta) * j
>
> >Eric, K7GNU
>
>
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